#include <iostream> #include <string> using namespace std; int main() { int number; int sum = 0;...
#include <iostream>
#include <string>
using namespace std;
int main()
{
int number;
int sum = 0;
while(true) {
cout << "Please enter a number between 1 and 11: ";
cin >> number;
if (number >= 1 && number <= 11) {
cout << number << endl;
sum = sum + number; //only add the sum when number is in range:
1-11, so add wthin this if case
} else {
cout << number << endl; cout << "Out of range;
rejected." << endl;
}
if(sum > 21)
break;
}
cout << "The total is " << sum << endl;
return 0;
}
works fine for everything but numbers out of the range im getting a program timed out error
Homework Answers
The reason why you get out of the range if the input number is not in range between 1 - 11 then it print out message
Out of range; rejected.
What the program does is . ?
it takes number 1 - 11 and sum up the number , if the number is not in range prints Out of range; rejected.,
if the sum of number exceed 21 . breaks the while loop and prints out the sum
Sample output:
Add Answer to:
#include <iostream>
#include <string>
using namespace std;
int main()
{
int number;
int sum = 0;...
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