Question

What partial pressure of N₂ gas (in mm Hg) is required to maintain a solubility of 4.17×10^-3 g/L in water at 25 °C? k_H for N₂ at 25 °C is 6.47×10^-4 mol/L·atm.

Answer 1

Answer:-

This question is solved by using the simple concept of Henry’s law of solubility of the gas in liquid which is directly proportional to the partial pressure of the gas over the solution.

The answer is given in the image,

Answer: z kya 6-47x10-4 mol/Laton Solubility = 4.14 x1d-3911 = 4•17x10 mol/l 28 = 1.49x10-4 moll solubility = KH. PM2 · PMy = solubility - 1.49x10-4 6.47X10-4 PM2 = D.230 atm PN2 = 0.230x760 mmHg PM2 = 175 mm dgn KH