Question

1-, - . 11. UN JUURUS NUVC Ucuncul VIC ! 2-2. A four-cylinder, two-stroke cycle diesel engine with 10.9-cm bore and 12.6-cm stroke produces 88 kW of brake power at 2000 RPM. Compression ratio re = 18:1. Calculate: (a) Engine displacement. [cm, L) (b) Brake mean effective pressure. [kPa] (c) Torque. [N-m] (d) Clearance volume of one cylinder. (cm)

Answer 1

I have plotted the compression process on pv graph so that you can understand the solution easily and also on the piston cylinder to understand it in a better way. I have used all the basics about the engine parameters and written all the formulas so that you can use them in future too.

4 cylindix 1uo shake L- 13.6 cm , B-P: 88 Kw He 18= VI V2 N2000 RPM ngine displacement (Va) oT V& Vd= V,-Va Vd T'L 4 Vd= 3.14 lo.9 V2 3 Vd I17515 Cm Vd 1.175 Vg=o.00175 m Vc. Bicak megs0 effective Ressuu (Pmm) BP- Pra Vs x N x k KNo of ylindu Pm Kaa175 X200 X 4 60 88- Cleanance Valume (Ve V2) hom D V-V3 Pm- 377.143 KPa 175.15 cm 4 Vh: 18 V2 18 V-V2 1175-1S Torq (T) BP- ANT V2Ve1175.1S 17 T 60 x80x103 Ry3.1400 Ve 63.126 Cm T 382.16 N-

Hope you like the solution. Thank you.