Question

An airline has found about 6% of its passengers request vegetarian meals. On a flight with 154 passengers the airline has 11 vegetarian dinners available. What's the probability that it will be short of vegetarian dinners? (hint: Let X be the number of vegetarians. Identify a probability model for X. Write a probability expression for that reflects "Short of vegetarian dinners and compute.) (Click to use an online probability calculator) (round to 4 decimal places)

Answer 1

Scd let x be random variable denotes the number of vegetarians 6% of its passengers request vegetarian meals p=0.06 n= 154 x ~Binomial (n=154, p=0.06) The probability mam function of ou P(X=x) = ((su (0.06) (100.06) ; x = 0,1,2 ... 154 The probability that it will be short of Vegelarian dinners- P(x>) - I-PLUS",) - l-E PCX=x) Isu-2 X = 0 21- $ (499) 60.003* (v0-06*** = 1 - 0.7847945 - 0. 21522548 ~ 0.2152