(A) moment estimation
E(X) =sum{ x*p(X=x)} = (3-thita)/3
=>4/10 =1-(thita/3)
=> thita/3 = 0.6
=> thita^ =1.8 answer
(B) MLE
Likelihood ={p( X=0)*p(X=1)}
=( thita/3)*(3-thita)/3 =(3*thita-thita^2)/9
Differentiate w.r.t thita and equate to zero
thita ^=3/2= 1.5
it shoud be 0<= theta<= 3. plz type it and answe both a and b. thank...
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