You have an ideal 17 V battery (no internal resistance) connected to the circuit shown above....
Three resistors are connected to an ideal battery (no internal resistance) as shown. The values are: EMF = 19 V R1 = 39 Ohms R2 = 70 Ohms R3 = 66 Ohms What is the total power output by the battery? Hint: You might consider the current through each individual resistor.
A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 22 Ω, R4 = R5 = 82 Ω and R2 = 147 Ω. The measured voltage across the terminals of the batery is Vbattery = 11.6 V. A circuit is constructed...
A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 24Ω, R4 = R5 = 112 Ω and R2 = 126 Ω. The measured voltage across the terminals of the batery is Vbattery = 11.73 V.2) What is r, the internal...
In the circuit shown, the voltage of the (ideal) battery is V = 39 V, and the resistances are R1 = 83 Ω , R2 = 58 Ω , R3 = 146 Ω , and R4 = 371 Ω . What is the voltage across the resistance R2? Give your answer in Volts to at least three significant figures, to avoid being counted incorrect due to rounding. Do not include units in your answer.
In the circuit shown above, a battery with a voltage ?Vbat = 24 V is connected to the circuit with resistances R1 = 5 Ohms, R2 = 35 Ohms, and R3 = 32 Ohms. The volt meter measures the potential difference between the points A and B, ?VAB. What is the power lost in the resistor R3? Give your answer in Watts to three signficant digits. Do not include units in your answer.
You have developed a new way to measure the internal resistance of a battery. The circuit you have created is shown below, with a non-ideal battery (EMF and internal resistance r in the red box), a constant external resistor R1-19.122, and a variable resistor R2. R2 has a resistance you can change over a wide range of values, from nearly zero to nearly infinity. In this circuit, you measure the voltage over R2, AV2. R1 is used to avoid damaging...
A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R = R3 = 40 N, R4 = Rs = 80 and R2 = 142 N. The measured voltage across the terminals of the batery is Vbattery = 11.41 V. I R R R R4...
In the circuit shown, V = 70 volts and the internal resistance of the battery can be considered negligible. (a) What is the equivalent resistance of the two resistor parallel combination? (b) What is the equivalent resistance for the entire circuit? (c) What is the total current flowing through the battery? (d) What is the current flowing through the 8 Ω resistor? (e) What is the current flowing through the 6 Ω resistor? (f) What is the current flowing through...
for circuit shown in figure the battery has no appreciable internal resistance. voltmeter and anmeter are ideal 2. (20 points, 5 points each) For the circuit shown in Figure, the battery has no appreciable internal resistance. Voltmeter and Ammeter are ideal. (a) What is the equivalent resistance of the circuit? 3 kn 2 kn R(series Rea» 3.734 3.21: 8-73 kn (b) What does the voltmeter read? parrele witn R4 . Vz4s τ24( 2 +): o.or7 (3.73 xu?): 47. 37lV (c)...
3 The emf of the battery in the complex circuit shown to below is 110 V. The resistance of four resistors are listed here: R1 = 10; R2 = 20; R3 = 20; R4 = 25 What is the current across resistor R4? (Please keep one decimal digit in your answer) 6 R1 w 9 12 R2 R3 M RA Your Answer: