Question

A survey found that social networking is popular in many nations around the world. Data was collected on the level of social media networking (measured as the percent of individuals polled who use social networking sites) and the GDP per capita based on purchasing power party (PPP) for 24 countries. Complete parts (a) through (c) Click the icon to view the data table a. Compute and interpret the coefficient of correlation, The coefficient of correlation, r = indicates (1) - correlation. (Round to three decimal places as needed.) b. At the 0.05 level of significance, is there a significant linear relationship between GDP and social media usage? Determine the hypotheses for the test. Choose the correct answer below, O A. Ho p=0 OB. Ho Bo=0 0 C. He B =0 H, p#0 Hy Po 70 | H, P > 0 OD. Hypso O E. Ho 3,20 OF. Hop20 Hyp> 0 H, B,<0 H,P<0 Compute the test statistic. ISTAT (Round to two decimal places as needed.) Identify the p-value of the test statistic. D-value = (Round to three decimal places as needed.) Reach a decision (2) - Ho There is (3) evidence to conclude that there is a significant linear relationship between GDP and social media usage c. What conclusions can you reach about the relationship between GDP and social media usage? O A. There is a significant linear relationship, but the positive linear relationship is only moderate. OB. There is not a significant linear relationship. O C. There is a significant linear relationship, and the positive linear relationship is perfect. O D. There is a significant linear relationship, but the negative linear relationship is only moderate

Answer 1

	ΣX	ΣY	Σ(x-x̅)²	Σ(y-ȳ)²	Σ(x-x̅)(y-ȳ)
total sum	227188	1009	833988537.3	5757.0	1743464.83
mean	9466.17	42.04	SSxx	SSyy	SSxy

correlation coefficient ,    r = Sxy/√(Sx.Sy) =   0.796

moderate relation

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slope hypothesis test   
Ho:   ß1=   0          
H1:   ß1╪   0          
n=   24              
alpha =   0.05              
estimated std error of slope =Se(ß1) = Se/√Sxx =    9.798   /√   833988537.33   =   0.0003
                  
t stat = estimated slope/std error =ß1 /Se(ß1) =    0.0021   /   0.0003   =   6.16
                     
Degree of freedom ,df = n-2=   22              
p-value =    0.0000              
decison :    p-value<α , reject Ho              
Conclusion:   Reject Ho and conclude that slope is significantly different from zero              

O A. There is a significant linear relationship, but the positive linear relationship is only moderate.

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