Question

A hollow metal sphere has inner and outer radii of 20.0 cm and 30.0 cm, respectively. As shown in the figure, a solid metal sphere of radius 10.0 cm is located at the center of the hollow sphere. The electric field at a point P, a distance of 15.0 cm from the center, is found to be E₁ = 3.05

Answer 1

please extend the time and raise the point to 1500 because question is complex and lengthy

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sorry for multiple post

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Answer 2

please extend the time and raise the point to 1500 because question is complex and lengthy

i will answer for sure

sorry for multiple post

i am writing your answer

Answer 3

The field at 15 cm is due to the charge on the inner sphere of radius 10 cm. And that has to be negative in nature as the field is inwards
Now the field at 35 is due to algebraic sum of charges (all the three)
If Q1 is the negative charge then E1 = K * Q1 /(0.15)^2
If Q is the total then E2 = K Q / (0.35)^2
Now being equal we get Q / Q1 = (0.15/0.35)^2
Right from E1 you could find Q1 and from above you can get Q.
But Q = Q1 + Q2 + Q3
Now Q2 + Q3 could be got. But you have to think so deep to find Q2 and Q3. All the best dear
Note: By Gauss's theorem field inside a charged sphere is 0
Field due to charged sphere is the same as if the charge is concentrated at the center.