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1 Write a function called sum_odd that takes two parameters, then calculates and returns the sum of the odd numbers between t

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Answer #1

I have used jupyter notebook, python 3, to solve your problem:

------------------------Code with comments--------------------------------------

# function
def sum_odd(number1,number2):
  
# declaring variable to calculate sum of odd numbers and initialised with zero
oddSum = 0
  
# looping from number1 to number2 using range function
# second argument not included in range function
# (loop)
for i in range(number1,number2+1):
  
# checking the number "i" is even or odd, if odd then this condition is true
# (decision structure)
if i%2 == 1:
# adding "i" to oddSum variable
oddSum = oddSum + i
  
# returning the oddSum as it contains the sum of odd numbers in the range of number1 and number2
# both are included
# (returning final sum)
return oddSum

sum = sum_odd(0,5)
print(f"Sum of odd numbers is {sum}")

----------------------Code Ends----------------------------------

Code Images:

# function def sum_odd(number1, number2): # declaring variable to calculate sum of odd numbers and initialised with zero oddS

-------Some outputs------------------------

sum = sum_odd(0,5) print(Sum of odd numbers is {sum}) Sum of odd numbers is 9 sum = sum_odd(6,10) print(Sum of odd numbers

= sum sum_odd(7,7) print(Sum of odd numbers is sum}) Sum of odd numbers is 7

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