Question

A man is out fishing with his daughter. They are initially sitting at opposite ends of their 3.00-m canoe, which has a mass of 60.0 kg and is at rest in the middle of a calm lake. The man and the daughter then carefully trade places. We will neglect any resistive forces between the canoe and the water. Note that you will most likely get different numbers for the different parts below. As usual, a good way to handle that is to solve the problem using variables, and only plug in numbers at the end.

a)

b)

Answer 1

A handwritten solution for this question is given below

for the first care - center of Mass – o- (24.0) + (60*15)+ (2 243.) (24+60+72) 1.962 m for the second care ! - center of mass - 72x0+ 60x1.5+ 24x 3 244 60r72 >> 1.04 m . s. displacement of canoe a 11.962 -104) = 0.923m & According to conservation of momentum (72x1-5) - (4x1.5) = (92+ 24 + 60) x v man's velocity girl relocity Totat mas mass relocity's directions as the - sign are is operated opposite. - ve 0.462 m/s