Question

PYTHON

PART 1) SIMPLE IF STATEMENTS INSIDE A LOOP. The first part of your program should do the following: • Write a section of code that prints off the numbers from 50 to 100. • It should also print off the letter grade that goes with that number on the same line using an if statement

o 0 – 59 = F

o 60 – 69 = D

o 70 – 79 = C

o 80 – 89 = B

o 90+ = A

Answer 1

Source Code:

Х 1.py - C:/Users/Kumar Reddi/Desktop/1.py (3.8.2) File Edit Format Run Options Window Help #print header print ("Score\tGrade") #for loop to print numbers from 50 to 100 for i in range (50,101): #print number print (i, end="\t") #check for F grade if(i<60): print ("F") #check for D grade if(i>=60 and i<70): print ("D") #check for C grade if(i>=70 and i<80): print("C") #check for B grade if(i>=80 and i<90): print ("B") #check for A grade if(i>=90): print ("A")

Output:

TI Python 3.8.2 Shell File Edit Shell Debug Options Window Help Python 3.8.2 (tags/v3.8.2:7b3ab59, Feb 25 2020, 22:45:29) [MSC tel)] on win32 Type "help", "copyright", "credits" or "license (). for more inf >>> RESTART: C:/Users/Kumar Reddi/Desktop/1.py Score Grade 50 F 51 F 52 F 53 F 54 F 55 F 56 F 57 F 58 F 59 F 60 D 61 D 62 D 63 D 64 D 65 D 66 D 67 D 68 D 69 D 70 с 71 172 73 74 75 С 76 С

С С С B B B B 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 B B B B B 92 93 94 95 96 97 98 99 100 B A A A A A A A A A A A

Code in text format (See above image of code for indentation):

#print header
print("Score\tGrade")
#for loop to print numbers from 50 to 100
for i in range(50,101):
#print number
print(i,end="\t")
#check for F grade
if(i<60):
print("F")
#check for D grade
if(i>=60 and i<70):
print("D")
#check for C grade
if(i>=70 and i<80):
print("C")
#check for B grade
if(i>=80 and i<90):
print("B")
#check for A grade
if(i>=90):
print("A")