Question

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Please answer question 2 (I got 1 already).

NOTE: The first picture is the exercise, the second is the question (question 2)  and the third picture (with blue lines) are class-notes I took to help you answer the question correctly. Thanks.

Answer 1

Given that

                                                     

M(f)= i27f, f <1

                                                      

Mf) = 0, otherwise

Since phase deviation is given by

                                     

o(t) = 2 Akt m(t) dt - -

So

                                       

MA) of) = 27 kf

So, we have

                                           

of) = 21 kr. f <1

                                           

of) = 0, otherwise

So time domain expression phase deviation is

                                       

0(t) = Jf=- (f)e2aft df

                                   

064) = 25 ks | 12:54df Jf=-1

Phase deviation is given by

                                 

2 kf sin(27) o(t) = ?