Question

The circuit shown above consists of a single battery, whase emf is 1.2 v, and three wires made of the same material, but having different cross-sectional areas. Each thick wire has cross-sectional area 1.4e-6 m2, and is 17 cm long. The thin wire has cross-sectional area 5.5e-8 m2, and is 3.7 cm long. In this metal, the electron mobility is 3e-4 (m/s)(V/m), and there are 5e+28 mobile electrons/m3 Which of the following statements about the circuit in the steady state are true? The magnitude of the electric field at locations D and Fis the same. The magnitude of the electric field at locations F and C is the same. The electron current at location D is the same as the electron current at location F At location B the electric feld points toward the top of the page The symbol EF represents the magnitude of the electric field at location F, and the symbol Ep represents the magnitude of the electric field at location D. Which of the following equations is a correct energy conservation (loop) equation for this circuit, following a path that starts at the negative end of the battery and goes counter-clockwise? 0 = +1.2V-EF*0.17m-ED*0.037m-EF*0.17m 0--1.2V + EF*0.17m + ED#0.037m + EF*0.17m 0-1.2V EF*0.17m Ep*0.037m EF*0.17m 0 1.2V EF 0.17m ED*0.037m EF 0.17m 1.2VE*0.17m 1.2V = ED* 0.037m The symbol İF represents the electron current at location F, etc. which of the following equations is a correct charge conservation 〔node) equation for this circuit? İF + İD-0 2"İF-İD Use the appropriate equation(s), plus the equation relating electron current to electric field, to solve for the factor that goes in the blank below Use the appropriate equation(s) to calculate the magnitude of ED V/m Use the appropriate equation(s) to calculate the electron current at location D in the steady state

Cross section area "e" refers to powers of ten i.e. 1.4e-6 meters = 1.4*10^-6 meters

Answer 1

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