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Please show all work A chemist titrates 60.0 mL. of a 0.2648 M aniineHNH2) solution with...
A chemist titrates 140.0 mL of a 0.0952 M aniline (CGH-NH2) solution with 0.7849 M HBr solution at 25 °C. Calculate the pH at equivalence. The pK; of aniline is 4.87. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added.
A chemist titrates 50.0 ml. of a 0.6210 Maniline (CH NH) solution with 0.2970 M HNO, solution at 25°C. Calculate the ph at equivalence. The pK, of aniline is 4.87 Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO, solution added. pH- x 5 ?
A chemist titrates 220.0 mL of a 0.5695 Maniline (CH, NH,) solution with 0.2844 M HNO, solution at 25 °C. Calculate the pH at equivalence. The pKor aniline is 4.87 Round your answer to 2 decimal places Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HINO, solution added pH- oll ? X
A chemist titrates 130.0 mL of a 0.0647 M methylamine (CH3NH2 solution with 0.5334 M HNO3 solution at 25 °C. Calculate the pH at equivalence. The p K, of methylamine is 3.36 Round your answer to 2 decimal places Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO3 solution added pH =
A chemist titrates 190.0 mL of a 0.4393 M hydrochloric acid (HCI) solution with 0.1456 M NaOH solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added. pH = [] Х 5 ? Calculating the pH of a weak acid titrated with a strong base An analytical chemist is titrating...
An analytical chemist is titrating 239.5 mL of a 0.2900 M solution of aniline (CHNH, with a 0.3800 M solution of HNO3. The p K of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 107.9 mL of the HNO2 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO2 solution added. Round your answer to 2 decimal places....
A chemist titrates 220.0 mL of a 0.4168 M pyridine CHN solution with 0.5811 MHBr solution at 25 C. Calculate the pH at equivalence. The pK of pyridine is 8.77. Round your answer to 2 decimal places Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added pH ? Ar
A chemist titrates 250.0 mL of a 0.5659 M lidocaine (C14H21NONH) solution with 0.4276 M HBr solution at 25 °C. Calculate the pH at equivalence. The pK, of lidocaine is 7.94. Round your answer to 2 decimal places Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. PH -
A chemist titrates 150.0 mL of a 0.4938 M sodium hydroxide (NaOH) solution with 0.6911 M HNO, solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO2 solution added. pH = 0
A chemist titrates 150.0 mL of a 0.1029 M potassium hydroxide (KOH) solution with 0.8645 M HCl solution at 25°C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HCl solution added. x 5 ?