H0: 230
Ha: > 230
7)
Test statistics
t = ( - ) / ( S / sqrt(n) )
=( 230.7 - 230) / ( 41.8 / sqrt(177) )
= 0.223
8)
From T table,
With test statistics of 0.223 and df of 176,
p-value = 0.4118
Question 6 Golf-course designers have become concerned that old courses are becoming obsolete since new technology...
(1 point) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 235 yards on average. Suppose a random sample of 131 golfers was collected and their sample mean driving distance was 234.4 yards. The population standard deviation is 49.9. Use a...
(6 points) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 250 yards on average. Suppose a random sample of 140 golfers be chosen so that their mean driving distance is 248 yards. The population standard deviation is 44.7. Use a...
(6 points) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 240 yards on average. Suppose a random sample of 101 golfers be chosen so that their mean driving distance is 239.6 yards. The population standard deviation is 43.5. Use a...
Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 250 yards on average. Suppose a random sample of 198 golfers be chosen so that their mean driving distance is 248.8 yards. The population standard deviation is 47.3. Use a 5% significance...
(1 point) Golf course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 235 yards on average. Suppose a random sample of 151 golfers be chosen so that their mean driving distance is 234.7 yards. The population standard deviation is 40.9. Use...
(6 points) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 240 yards on average. Suppose a random sample of 101 golfers be chosen so that their mean driving distance is 239.6 yards. The population standard deviation is 43.5. Use a...