Question

4) A marketing executive is creating a commercial for a new drug that treats insomnia. Using the same voiceover script, he wants to know which one of three images people prefer to see: 1) a person who cannot sleep at night, 2) a person who is sleeping soundly at night, or 3) a person who is very sleepy during the day. He made four focus groups (comprised of individuals with difficulty sleeping) and showed them all three of the commercials. Each group rated the commercials on a scale of 1-10 (with 1 being least likely to use the new drug and 10 being most likely to use the new drug). The results are presented in the table below Commercial 1 2 3 Faces Group 1578 Faces Group 26 6 8 Faces Group 4 3 Focus Group 45 66 Focus Group 54 77 45 6.0 64 1.141.220 X-519, G-85 a. What type of hypothesis test do you need to use? (1 point) b. Are the results significant at a 0.01? (Final answers should include a comparison of your calculated test- statistic compared to the critical value e.g., 5.71 > 4.5) (4 points) c. Determine the effect size using an appropriate equation (Cohen's dr/n) (2 points) d. Write the full results in APA format (including appropriate statistical data and grammatically correct sentences that take into account the question question) (2 points) e. If necessary, calculate Tukey's HSD, and compare otherwise write "N/A" (1-2 points)

Answer 1

(a) One-Way ANOVA test

(b) The output is:

	Mean	n	Std. Dev
	4.6	5	1.14	Commercial 1
	6.0	5	1.22	Commercial 2
	6.4	5	2.07	Commercial 3
	5.7	15	1.63	Total
ANOVA table
Source	SS	df	MS	F	p-value
Treatment	8.93	2	4.467	1.89	.1938
Error	28.40	12	2.367
Total	37.33	14

The calculated test statistic is 1.89.

The critical value is 6.93

Since 1.89 < 6.93, we cannot reject the null hypothesis.

(c)

Source	effect size
Treatment	0.2392857
Error	0.7607143

(d) The full output is above and the plot is as follows:

Comparison of Groups Commercial 1 Commercial 2 Commercial 3

(e) Not necessary because the p-value is not less than 0.01.

SO, N/A.

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