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Q2 [40 points) A survey is conducted to find out whether people in metropoli- tan areas obtain their news from television (Ev
a) What is the proportion of those who obtain news from television, but not newspapers? 2 b) What is the proportion of those
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Answer #1

From given informationwe have

P(T)=0.60,P(N)=0.60,P(R)=0.50

P(T\cap N)=0.30,P(T\cap R)=0.25,P(N\cap R)=0.30,P(T\cap N\cap R)=0.15

a)

P(T\cap N')=P(T)-P(T\cap N)=0.60-0.30=0.30

Answer: 30%

b)

By the addition rule of probability we have

P(T\cup R)=P(T)+P(R)-P(T\cap R)=0.60+0.50-0.25=0.85

By the complement rule, the required probabilit is

P[(T\cup R)']=1-P(T\cup R)=1-0.85=0.15

Answer: 15%

c)

By the addition rule of probability we have

P(T\cup N\cup R)=P(T)+P(N)+P(R)-P(T\cap N)-P(T\cap R)-P(R\cap N)+P(T\cap N\cap R)=0.60+0.60+0.50-0.30-0.25-0.30+0.15=1

By the complement rule, the required probabilit is

P[(T\cup N\cup R)']=1-P(T\cup N\cup R)=0

Answer: 0%

d)

P(N|R)=\frac{P(N\cap R)}{P(R)}=\frac{0.30}{0.50}=0.60

Answer: 60%

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