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The distance from town X to town Y is 200 km. The distance from town X to town Z is 135 km. Looking from town Y, town X and t

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T 4200 2ookm X 135km N. According to the q ustion we draw the possible diagrams for this condition The diagram make a trianglTherefore OR Sinx Siny YZ x z Sin55 6 = Sin42° yz 135 y2 = 135X Sin55-6 sin 420 13500.825135 0.66913061 = 111.3903225 0.66913

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