Question

For the following questions, i) state clearly the shear force and bending moment equations and ii) draw the shear force and bending moment diagrams. Please answer both

10 kN 2 kN/m 5 m 3 m —+-2 m 8 kN/m 4 m -

Answer 1

2 kN/m Salt 21Nm í Etter JOEN E MAOP Armas +3m- Am RD RA1 axt V KB (lo-x) 9.5KN Reactions- EFV-0 = RA+ Rp = 2x5 + 10 - 20 kg EMA:02x5x5) + lox(5 + 3) - Roxio - RB = 10.5 IN RA= 9.5 IN Section ACCLEO to5m) Shear force Vxy? 9.5-2x" Bending Mo. Max: 9,54-22+ = 9.5-x2] ata (x=0) = VA» 9-5 ICN,MA:O C(7:5) Vc = --5 KN, Mc= 225 KN. zero she qe - Vx-x=0 + X9.5 = 4.75 af7a4-759Mx = 9.5x4.75 -4.75 - 22-5625 KN-M *5 KN 15.fipal -& -+ 4.75m -10.5 IN 22,5625 - 22.5 EN- KN-m 21 ON-M B [Nxx= 9.5-5x2= -0.5kN - Vlo=05 KN MXX = 9.5x-1012-2015) = 25--52 MD 21 KM Section OB CAXE Stocom) TV 42-L0.5 KM ]-VO-VB [Mx-x= 10.5 10 - x) MB: 0

X SKNlm ť da im kazm &x- AN X (6-2) 16 KN 12 KN X=1.5ml Reactions- Ely : 0 X Rat Rp = 8X6= 48 KN EMAO » 8x666/= RB X 4 - RB = 36 KN RA= 12 KN Section AB(x=0704m shear force Mx x = 12-8x Bend. Moneo - Mexx = 122-822/2-122-422 at A (x-1) => VA= 12 ICN MAO aud B (-4 m) + Vp :-20 kN Mo = -16 ION-me zero she98 - Vxx=0" 12-8720 +4:1-5m Mat 2-[-5m - M: 1281-5-481-52 = 9 ICNAM. section Be (x=4 to 6m) . at B x=4. [Vxx = + 8 (6-x)] 1/B = 16 KN MR = - 16 KN-m z w atc - Y=0 M = 0 (S.FD] - 20 KN 19 KN-m IB c B.M.D. M . - 16kn-m
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