This second question has multiple parts that are not shown until each question is answered.
ans)
from above data that
According to the given data:
The percent of the acid molcules that are ionized = {[acid]equilibrium/[acid]initial}*100
= {[HClO2]consumed/[HClO2]initial}*100
= {([HClO2]initial-[HClO2]equilibrium)/[HClO2]initial}*100
= {(0.1 - 7.09*10-2)/0.1}*100
= (2.91*10-2/0.1)*100
= 29.1%
This second question has multiple parts that are not shown until each question is answered. HCIO2(aq)...
Calculate the equilibrium concentrations of all chemical species present in a 0.10 M H CO.(aq) solution. What is the percent ionization of the acid and resulting pH? Units Units [H2CO3) = Number [HCO3) = Number [CO32) = Number [H30+) = Number Units Units % ionization = Number pH = Number Ka Acid Acetic Ammonium Formula CH3COOH NH4+ H3B03 1.8 x 10-5 5.6 x 10-10 5.4 x 10-10 Boric Carbonic H2CO3 Chlorous Formic Hydrocyanic Perchloric HCIO2 HCOOH HCN HC104 4.5 x...
QUESTION 19 Which compound listed below has the smallest molar solubility in water? CdCO3 (Ksp = 5.2 x 10-12) ОА. OB. Ca(OH)2 (Ksp = 2,5 x 10-14) OCAgI (Ksp = 8.3 x 10-17 OD.CaF2 (Ksp = 3.9 x 10-11) OE ZnCO3 (Ksp = 1.4 x 10-11) QUESTION 20 Click Save and Submit to save and submit Chek Saue Al Anser to save alters ve here to search Remaining Time: 1 hour, 05 minutes, 02 seconds. * Question Completion Status: QUESTION...