HI I NEED JUSTIFICATIONS, PLEASE HELP ME UNDERSTAND THANKS!! :)
Answer a.
This is based on Central Limit Theorem which states that "For large sample sizes, the distribution of sample mean is approximately normal irrespective of the distribution of the random variables".
Therorefore, here since the distribution is unknown and the sample sizes are large so the approximate confidence interval for will be based on quantiles of Normal Distribution.
Answer b.
This is based on the fact on which the t-distribution is based. The following assumptions must be satisfied in order to use t-distribution for Difference in Means:
1. The Population from which the samples are drawn must be Normal.
2. Population Variances must be equal.
3. Population Variances must be unknown.
Here, since population variances are equal but unknown and the population is Normal, so we can obtain the exact confidence interval of Difference in Means using t-distribution.
Answer c.
This is because there is no information on the sample sizes and also if sample sizes were to be assumed large, then too we would have obatined an approximate confidence interval for Difference in Means based on Central Limit Theorem. For large n, Binomial do not tend to t-distribution
Hence, Binomial Distribution cannot be approximated by t-distribution.
Answer d.
This depends on the application of Central Limit Theorem which says that for large n the Binomial Distribution tends to Normal DIstribution.
So the approximate Confidence Interval would be based on quantiles of Normal DIstribution.
Note: Wherever Central Limit Theorem is applied, we will always obtain Approximate Normal Distribution and hence approximate Confidence Intervals.
HI I NEED JUSTIFICATIONS, PLEASE HELP ME UNDERSTAND THANKS!! :) 2. [4 points) Let X1,..., Xn...
hi..please help me to solve these problem. (15 marks) 3. Xi, X2, Xs, X4 is a random sample from the Normal (0, 4) distribution. We want to test HO: θ 15 versus Hi: θ< 15. Let X_13x (a) Suppose we have two decision rules: Reject Ho if and only if () X <IS (II) X <12 Which one is better and why? (b) Instead of n 4, let n be an unknown. Let the decision rule now be: Reject Ho...
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iid 20. Let X1, ...,Xn - Exp(a), the exponential distribution with failure rate 2. We showed in Sections 7.2 and 7.3 that â= 1/X is both the MME and the MLE of 2, and that its asymp- totic distribution is given by vn (Å - 1) PW~N (0,22) (8.53) Use the normal distribution in (8.53) to obtain, via a variance stabilizing transformation, an approximate 100(1 – a)% confidence interval for a.
for these questions I need help on just the questions on all of them where it says "what is the value of the sample test statistic?" 24.) The average annual miles driven per vehicle in the United States is 11.1 thousand miles, with σ ≈ 600 miles. Suppose that a random sample of 36 vehicles owned by residents of Chicago showed that the average mileage driven last year was 10.9thousand miles. Does this indicate that the average miles driven per...
Hi I'm wondering if you can help me with this question please? Thanks! Suppose we would like to make a confidence interval for the proportion of Americans who support "gun control Which of the following statements is TRUE? Select one: O a. The exact probability that a confidence interval contains the population proportion is always higher for a 95% confidence interval than a 90% confidence interval. Cross out o b . A 90% confidence interval obtained from a random sample...
need help. please this question hace more parts! please i want to put the rest in the comments. so you cna help me out! WSUIT Help Use the standard normal distribution or the distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results In a random sample of 13 mortgage institutions, the mean interest rate was 3.56% and the standard deviation was 0.37%. Assume the...
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show me all work for the problem i,ii,iii Exercise 1 (Sample size for estimating the mean). Let X1,...,x, be i.i.d. samples from some un- known distribution of mean u. Let X and S denote the sample mean and sample variance. Fix a E (0,1) and € >0. (i) Suppose the population distribution is N(uo?) for known op > 0. Recall that we have the following 100(1 - a)% confidence interval for : (1) Deduce that plue (x-Zalze in 2+ zarze...
A random sample of 49 measurements from a population with population standard deviation o 3 had a sample mean of x, 9. An independeent random sample of sample mean of x, 11. Test the claim that the population means are 64 measurements from a second population with population standard deviation a2 4 had different. Use level of significance 0.01. (a) What distribution does the sample test statistic follow? Explain. The student's t. We assume that both population distributions are approximately...
Let X1 Xn be a random sample from a distribution with the pdf f(x(9) = θ(1 +0)-r(0-1) (1-2), 0 < x < 1, θ > 0. the estimator T-4 is a method of moments estimator for θ. It can be shown that the asymptotic distribution of T is Normal with ETT θ and Var(T) 0042)2 Apply the integral transform method (provide an equation that should be solved to obtain random observations from the distribution) to generate a sam ple of...