weight of the body
1 lb = 4.4482216282509 N
w = 250 lb= 1112.05540706273 N
m = w/g = 1112.05540706273 N/9.8 m/s^2 = 113.47 kg or 7.77 slug
(b)
weight of the body on moon
w= mg _ moon = 113.47 kg (9.8/6) = 185.34 N or 41.66 lb
A body weighs 250 16, at the earth's surface. Determine: a) The mass of the body....
Please explain step by step! Useful Planetary Data Mean Radius (m) 243 × 106 6.06 × 10° 6.38 × 10° 3.37 × 106 6.99×107 5.85 × 10' 2.33 × 107 221 × 107 1.14 × 10° 1.74 × 10° 696 × 108 Period (s) 7.60 × 106 1.94 × 107 3.156 × 10, 5.94 × 10' 3.74 × 108 9.35 × 108 2.64 × 109 5.22 × 109 782 × 109 Mean Distance from Sun (m) 579 × 100 1.08...
Table 13.1 Solar system data (in SI units and relative to Earth) Orbit eccentricity Mass Equatorial radius semimajor axis period (a^) (years) 30 Sun 2.0 X 10 3.3 × 10 Mercury 3.30 X 1023 Venus 4.87 X 1024 Earth Mars Jupiter 1.90 x 1027318 Saturn 5.68 × 1026 95.2 Uranus 8.68 X 1014.5 Neptune 1.02 x 102617.1 Pluto 2.440 ×106 6.052 X 106 6.378 X 106 3.396 × 106 5.79×1010 1.082 x 1011 1.496 × 1011 2.279 ×1011 11.2 7.783...
Pluto -1.4 x 10 1.5 x 10 1.02 X 1 Moon 7.36 x 1022 1.991 x 1030 1.74 x 106 6.96 x 108 Sun -13 POINTS SERCP11 7.5.P.044. A 716-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m /s (b) Find the period of its revolution. (c) Find the gravitational force acting on it. Need Help? Read it -18 POINTS SERCP9 7.P.031.MI.FB. A...
Please use the formulate sheet and show all steps to make sure the question is worth any points a) The initial ratio of deuterium (D) to hydrogen (H) in a planet's atmosphere was 175000; however, the present ratio is 1/1500 and the initial and final abundances of D are 5 x 10° atoms per m3 and 9 x 106 atoms per m2, respectively. What fraction of deuterium has been lost, and what fraction of hydrogen has been lost in this...