Question

A sample of oxygen gas was collected via water displacement. Since the oxvgen was collected via water displacement, the sample is saturated with water vapor. If the total pressure of the mixture at 26.4 ? is 725 torr, what is the partial pressure of oxygen? The vapor pressure of water at 26.4 °C is 25.81 mm Hg Number torr

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Answer #1

25.81 mmHG is approximately equal to 25.81torr

P(total) = P(O2) + P(H2O)

725 = P(O2) + 25.81

P(O2) = 699.19 torr

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