Interference at glass-air interface. Based on the diagram on the left-hand side, calculate the minimal thickness (d) of glass plate when ray 1 and ray 2 have a constructive and a destructive interference.
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Interference at glass-air interface. Based on
the diagram on the left-hand side, calculate the minimal thickness...
The default setting is a thin film of glass(n = 1.5) with air (n = 1)on...
The default setting is a thin film of glass(n = 1.5) with air (n
= 1)on both sides.The starting wavelength is 652 nm and the
starting thickness is 544 nm. Use these starting values for this
next set of questions.
1. Is there a phase shift on the front (left) interface? On the
back (right) interface in the simulation?Justify why there is/isn’t
a phase shift at each interface.
2. How does the wavelength in the film (glass) compare to the...
Thin Film Interference Problems 1. Oil (n=1.25) floats on water. What is the minimum thickness of...
Thin Film Interference Problems 1. Oil (n=1.25) floats on water. What is the minimum thickness of oil in a region where it appears green ( = 525 nm)? (Ans: 210 nm) 2. A 500 nm thick layer of oil (n = 1.25) floats on water. What wavelengths of light in the visible range (400 nm to 700 nm) are maximally reflected? (Ans: 417 nm, 625 nm) 3. Athin film of acetone (n = 1.25) coats a thick glass plate (n...
A thin air gap between two refractive materials with n =1.3 and n2-1.8 is shown in...
A thin air gap between two refractive materials with n =1.3 and n2-1.8 is shown in the diagram. The gap is the thinnest possible so that totally destructive interference occurs between ray 1 and ray 2, for light of a particular wavelength I. What is the effective phase difference A931 = 03 - 01 between ray 3 and ray 1? 1 1 1 n=1.3 Air n=1.8 Oo O 0.31 I/2 Оп Impossible to calculate without knowing
Question 5: How would dust and oil on the glass plates affect the results? EXPERIMENT 10 THIN FILM I...
Question 5:
How would dust and oil on the glass plates affect the
results?
EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a...
I) Sketch a ray diagram of a normally polarized electromagnetic field interacting with a glass/ai...
i) Sketch a ray diagram of a normally polarized electromagnetic field interacting with a glass/air interface. Calculate the critical angle for the glass/air interface (nI(pure glass).5; n2(air)-l). For this calculation, you can ignore the polarization because the critical angle is the same for either normal or parallel normalisation. ii)Derive an expression for the wavelength of the transmitted wave as a function of the refractive index ni at®i-0c from the phase matching boundary requirement at the glass/air interface (see Fig. 1)....
Question 6: What percentage error would result from miscounting the bars by one? EXPERIMENT 10 THIN...
Question 6:
What percentage error would result from miscounting
the bars by one?
EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a known...
A light ray in air (n= 1) is incident on a thin film of oil (noil...
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
water interface (the surface of the lake), it is partly reflected back into the air and...
water interface (the surface of the lake), it is partly
reflected back into the air and partly refracted
or transmitted into the water. This explains why on the surface of
a lake sometimes you see the reflection of the surrounding
landscape and other times the underwater vegetation.
These effects on light propagation occur because light travels at
different speeds depending on the medium. The index of refraction
of a material, denoted by n, gives an indication of the speed of...
10.A narrow beam of white light is incident normally on the surface of a triangular silicate...
10.A narrow beam of white light is incident normally on the surface of a triangular silicate flint glass prism with one angle of 90. The index of refraction for violet light is 1.66 and for red light is 1.61. The angle in the prism is equal to 30° of glass. a. On the diagram below show an approximate sketch for the refracted light from the opposite face of the prism. Air B White light 780° Glass Calculate angular separation between...
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it ...
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it is always bent away from its original path. This process is known as refraction and the change in direction depends on the change in optical density (or refractive index) of the two materials. A larger change in refractive index results in a larger change in angle between incoming and outgoing light beams. A light beam bends closer to the normal in the material with...
The default setting is a thin film of glass(n = 1.5) with air (n
= 1)on both sides.The starting wavelength is 652 nm and the
starting thickness is 544 nm. Use these starting values for this
next set of questions.
1. Is there a phase shift on the front (left) interface? On the
back (right) interface in the simulation?Justify why there is/isn’t
a phase shift at each interface.
2. How does the wavelength in the film (glass) compare to the...
Thin Film Interference Problems 1. Oil (n=1.25) floats on water. What is the minimum thickness of oil in a region where it appears green ( = 525 nm)? (Ans: 210 nm) 2. A 500 nm thick layer of oil (n = 1.25) floats on water. What wavelengths of light in the visible range (400 nm to 700 nm) are maximally reflected? (Ans: 417 nm, 625 nm) 3. Athin film of acetone (n = 1.25) coats a thick glass plate (n...
A thin air gap between two refractive materials with n =1.3 and n2-1.8 is shown in the diagram. The gap is the thinnest possible so that totally destructive interference occurs between ray 1 and ray 2, for light of a particular wavelength I. What is the effective phase difference A931 = 03 - 01 between ray 3 and ray 1? 1 1 1 n=1.3 Air n=1.8 Oo O 0.31 I/2 Оп Impossible to calculate without knowing
Question 5:
How would dust and oil on the glass plates affect the
results?
EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a...
i) Sketch a ray diagram of a normally polarized electromagnetic field interacting with a glass/air interface. Calculate the critical angle for the glass/air interface (nI(pure glass).5; n2(air)-l). For this calculation, you can ignore the polarization because the critical angle is the same for either normal or parallel normalisation. ii)Derive an expression for the wavelength of the transmitted wave as a function of the refractive index ni at®i-0c from the phase matching boundary requirement at the glass/air interface (see Fig. 1)....
Question 6:
What percentage error would result from miscounting
the bars by one?
EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a known...
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
water interface (the surface of the lake), it is partly
reflected back into the air and partly refracted
or transmitted into the water. This explains why on the surface of
a lake sometimes you see the reflection of the surrounding
landscape and other times the underwater vegetation.
These effects on light propagation occur because light travels at
different speeds depending on the medium. The index of refraction
of a material, denoted by n, gives an indication of the speed of...
10.A narrow beam of white light is incident normally on the surface of a triangular silicate flint glass prism with one angle of 90. The index of refraction for violet light is 1.66 and for red light is 1.61. The angle in the prism is equal to 30° of glass. a. On the diagram below show an approximate sketch for the refracted light from the opposite face of the prism. Air B White light 780° Glass Calculate angular separation between...
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it is always bent away from its original path. This process is known as refraction and the change in direction depends on the change in optical density (or refractive index) of the two materials. A larger change in refractive index results in a larger change in angle between incoming and outgoing light beams. A light beam bends closer to the normal in the material with...
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