Question

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A Rankine cycle steam generating plant operates with a condenser pressure of 0.05bar, high pressure steam enters the turbine at 30bar and 600°C and expands with an isentropic efficiency of 0.9%. Using the Enthalpy-Entropy diagram provided, determine the dryness fraction of the steam leaving the turbine. Your answer needs to be submitted to 2 decimal places. DO NOT INCLUDE UNITS IN YOUR ANSWER

Answer 1

I 600°c MA soban 005 bare 282 @ 30bas 600°c S = 7.508 kJ/k9t = 3681.0 kJ/kg (Isentropic) (foom subecheated steam table) ( " S2 = s.

- 340.6+ U9d06 JUU @ 0.05 bar Sf = 0.476 kJ/kg-K Sty= 7.920 KJ/Kg * So= 8.396 KJ KgK. Infe 1378 kilkg hpg = 2423.8 Kotka 32= SG + X 25 sfg 7.508= 0.476 + X 28 X 8.920 X2 = 0.8878 hash + 725 hag = 137.8 +0.887882423.8 has = 2289 - 840 kJ/kg (Nren = 0.9 = hi-has 3681.0-h2 hi has 3681.0 - 2289 440 ha - 24horass 2428.95 Kolkg

h2 = 2428.956 ROIKE hau eff X2 hfg 2428.956 = 137.8 +*24 2423.8 x2 = 0.94527 1. Aly. douness fraction of steam leaving the trobine & latitool) - 2