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Question 2 Picture it. Its 5 oclock on Friday and at the end of a long week all Dave wants to do is go home. But his boss h
Question 2 a) Will the beam fail? Design Data: Grade of steel, fxx = 500MPa Grade of concrete, tek = 30MPa Dead load (incl. s
2945 500 M.Rd=0.87.2945.500051 -0.77 250 - 505.30) M.Rd = 453kNm > 378kNm (okay!) Check Reinforcement Ratio pa 2945 505 250 1
M.Ra=0.87.2945-500-505. 1 -0.77 * 300-505 - 0.7250 - 505.30) M.Rd = 453kNm > 378kNm (okay!) Check Reinforcement Ratio 2945
Fs = As E E Fs = 2945 x 200 000 x .00189 Fs = 1113 kN Per as 08< b = 0.85 • . • 0,8 - 328 - 250 = 1115kN 0.8. 328. 250 = 1115
129 X 106 0.87.500.505. 0.9 652mm Try 2, 420mm diameter reinforcing bars, As - 628 mm2 M.sa = 0874-19d|1 - 0.27 M.Ra = 0.87 •
i have also attached the solutions.
could you please explain step by step what they are doing. especially the bit in part (a) where they do x/d
9 / 151 BAR CHART Areas of Groups of Bars (mm) Number of Bars Bar Size 1 5 6 7 113142170 198 50 101 201 252302 352 79 157 236
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Answer #1

While deegning the bear he f the f denforcenent Cateel) to caleulate the amount stp. beam and Caleulate the load. are :- TherNAimate Load 1.35 x Dead load + 1. Sx Live load. 21EN/m. %3D 1.35 x 10 1.5x S Oltmate load do the design f Lighe load for whiEfeetive DepR Calculation Renforcenent Cormpreon Reinfecement Cteoion) Shean lnka / shiraps Concete cover Effective depth g aCheck Remforcement aesuning yiolded steel Las In thes step until the calculated moment The be bending ealculate steel has Bennforcement Raho Check This cheek -ent dore to caleulate the remforcom ratio beam beam and detkimne if the Jenfred in under roEg -X 1- 0.0035 0. 00 22 %3D 0.0035 -1 0 0022 0.591 the so steel la not ypielded 500 0.0022 %3D X 2 X 1os Y, = Facto of safetApologies for the handwriting if you have any questions please let me know in the comment section below.

Have a nice day :)

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