Please explain why these are overflows. Also I do not understand how they got these numbers please show on paper how with good detail I am confused on these
Please explain why these are overflows. Also I do not understand how they got these numbers...
I don’t understand how they got the answer can someone please do it in detail so I can understand CHw01 Exercise 1.48 Part A Giv vectors A-400i +7.00, and E-5.00-2.00, firndthevetorproduct AxB Express your answer in terms of the unit vectors i, j, and k. Use the 'unlt vector button to denote unit vectors in your answer. en two
I need help with this assignment. My answers are in bold but I am not getting the correct output which is also below. Can you please take a look at it. #include <stdlib.h> #include <stdio.h> #include <float.h> #include <math.h> // PURPOSE: To define a nickname for type 'unsigned int'. typedef unsigned int uInt; //-- Sign related constants --// // PURPOSE: To tell how many bits to shift the sign field from the // least...
please explain fully. also I am confused why there are numbers in with E and Z (2.) Draw structures corresponding to the following names: a) (4E)-2,4-dimehyl-1,4-hexadiene b) Cis-3,3-dimethyl-4-propyl-1,5-octadiene c) 4-methyl-1,2-pentadiene d) (3E,5Z)-2,6-dimethyl-1,3,5,7-octatetraene e) 3-butyl-2-heptene f) Trans-2,2,5,5-tetramethyl-3-hexene
Please explain how they arrived at these numbers. I don't understand what to do when there is a cap or a limit on something. I don't understand which ones have caps and how to apply those to the problem. I understand what to do once the numbers are in this table. I just don't understand how to arrive at all these numbers. Also explain 2 ways to settle a capital deficiency please. The SAD partnership is to be liquidated. The...
Can someone explain me parts of this code I do not fully understand what its doing or what its purpose is. I have highlighted the parts I'm confused over. Please explain thoroughly. import java.util.Scanner; class A1Stats { public static void main(String args[]) { double min, max, sum, mean; int n; Scanner scanner = new Scanner(System.in); String input = scanner.nextLine(); String[] numbers = input.split(" "); double value[] = new double[numbers.length]; if(numbers.length > 0){ for (int i = 0; i < numbers.length;...
Please detail how to do at least one step-by-step, I do not understand how to do it. 4. (10 points) Convert these 32-bit, single-precision values into decimal numbers: a. Ox3fc00000 b. 0x807345ff C. Ox7f350000 d. Oxffffffff e. 0x20000000 f. 0x7f800000 g. Oxff800ffe h. 0x42c80000 i. Ox4d800000 j. 0x80000000
Please help in C: with the following code, i am getting a random 127 printed in front of my reverse display of the array. The file i am pulling (data.txt) is: 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 when the reverse prints, it prints: 127 9 8 7 6 5 4 3 2 1 0 9 8 7 6 5 4 3 2 1 not sure why...please...
Can you please explain how they got the answer for each question, I dont understand how to do them. Please explain it in great depth since I am a beiginner in Organic Chemistry. 77. Predict the product(s) for the following reaction. H3 H3 H3C H3C A) I B) II C) III D) IV E) none of these Ans: B 84. Predict the product(s) for the following reaction. 1.CH ONa 2 H2O OCH3 CH IV A) I B) II C) III...
HOW DOES THE CODE WORK AND PLEASE TELL ME WHERE DID THE NUMBER [J] COME FROM WHEN IT HASN'T BEEN DECLARED IN THE ABOVE STATEMENT MOREOVER KINDLY ALSO DRY RUN THE PROGRAM TO MAKE IT MUCH EASIER TO UNDERSTAND int main() { int i, j, a, n, number[i]; printf("Enter the value of N \n"); scanf("%d", &n); printf("Enter the numbers \n"); for (i = 0; i < n; i++) scanf("%d", &number[i]); for (i = 0; i < n; ++i) { for...
please help please explain how you got the answer. I dont understand the 1/2 part of it and how it goes along with the rest of the information. Review | Constants Periodic Table Which of the following set of quantum numbers (ordered n, l, m, m.) are possible for an electron in an atom? Check all that apply. ► View Available Hint(s) B-4.3, 1, 112 2.4.1. -1/2 23, 2, 2, -1/2 5.3.0.12 B 2, 1,0 5,3,4, 1/2 0 3.2.-3, 112...