Question

A block of mass M = 15 kg is suspended at rest by two strings attached to walls, as shown in the figure. The left string is horizontal and the right string makes an angle θ = 50° with the horizontal. What is the tension in the left string? (Assume the ring where the strings come together is massless.)

T_left =

Answer 1

Mass of the block(M) =15kg

The left string is horizontal and the right string makes an angle (θ )= 50° with the horizontal.

We know consider the tensions in each string

T1 and T2 are tensions in the string T1 be the tension in the horizontal string and T2 be tesion in the string which makes 50 degrees with thehorizontal.

Now as the system is in equilibrium then

Tension(T2) =mg (weight acting in the downward direction)

Now horizontal component of T2 =T1

From the vector diagram

tan50 =mg/T1 ===> T1 =mg/tan50 =(15)(9.81)/tan50 =147.15/1.1917=123.47N

This force will be acting towards the wall