2)
A)
Answer
0.7053M
Explanation
Molarity = no of moles per liter of solution
No of moles of NaOCl = mass of NaOCl/molar mass of NaOCl
No of moles of NaOCl = 5.25g/74.44g/mol
No of moles of NaOCl = 0.07053
Therefore,
molarity of NaOCl = (0.07053mol/100ml)×1000ml = 0.7053M
B)
Answer
0.0973M
Explanation
Dilution formula is
C1 × V1 = C2 × V2
C1 = initial concentration
V1 = Initial Volume
C2 = Final concentration
V2 = Final Volume
C2 = C1×V1/V2
C2 = 4ml × 0.7053M/29ml
C2 = 0.0973M
3)
Answer
2.0609g
Explanation
Molarity of solution 2A = 0.7053M
Molar mass of NaCl = 58.44g/mol
mass of NaCl required for 1L of solution= 58.44g/mol × 0.7053mol = 41.218g
mass of NaCl required for 50ml solution = (41.218g/1000ml)×50ml = 2.0609g
? 4. 4.1% at 630 nm solution . What is the absorbance of the solution? of...
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Question 1 5 pts The extinction coefficient for FD&C Blue Dye #1 is 138,500 cm-L/mol at 630 nm. A chemist collected the following data at 630 nm. She also found that the absorbance of an FDSC Blue Dye #1 solution of unknown concentration was 0.229. Use your graphing calculator to generate a standard curve from this data set, and use it to determine the concentration of the unknown solution. Express your answer in 10" (if your answer is 5.52x10-M then...
Question 1 5 pts The extinction coefficient for FD&C Blue Dye #1 is 138,500 cm-L/mol at 630 nm. A chemist collected the following data at 630 nm. She also found that the absorbance of an FD&C Blue Dye #1 solution of unknown concentration was 0.229. Use your graphing calculator to generate a standard curve from this data set, and use it to determine the concentration of the unknown solution. Express your answer in 10-5M (if your answer is 5.52x105M then...
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