Question 10 1 pts The molar solubility (in M) of PbCl2 in a 0.20 M solution...

Question

Question

Answer 1

Answer #1

PbCl2 ===> Pb2+ + 2Cl-
[Pb2+] * [Cl-]2 = 1.6*10-5
x * (0.2+x)2 =1.6*10-5

x*0.04 = 1.6*10-5

it will be B

Answer 2

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