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The system is released from rest with the cable taut, and the homogeneous cylinder does not slip on the rough incline. Determ

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Answer #1

ina N = 68.688 N uabo mo hon along cris 十 -21, 366 = 3.150L 3.15 α-T + 26.36G Lotahb)al moon about point o CamScanner1-575α 丁 2.36 2 5 α + 13-163 FBD K D moho al 103.98b- T 8.901, α , scann.TT ithlo3. 986-8.qOj α ·ㄧㄧㄧㄧ CamScannerns (2) and H 2.2625 +13183 l01-986 - 11.2665 α = 90.80 3 Tension in the cable,T 3-150( + 26 . 366 3-15(e-om)-32-22.+26.366 =

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