Question

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid load(II) sulfate (PbSO) is reduced to lead at the cathode and oxidized to solld lead(II)oxide (PbO) at the anode. Suppose a current of 98.0 A is fed into a car battery for 20.0 seconds. Calculate the mass of lead deposited on the cathode of the battery Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. db e X 5

Answer 1

Current 98.0A 98.0 cls { 1A = 16/} time a 20.9S i Total charge time x current 98.0x20.0 1960 C 1960 1.602 X10-19 number electrons 1960 moles Pb² tag + ze a Pb (s) number of atoms of Pb deposited atoms 2x1.602x10-19 lead (Pb) deposited 1960 2x1.602 810-19 6.022x1023 1.0158 x 10-2 mol of lead = 207.2 g/mol of lead deposited 207.2 x 1.0158 x 10-2 = [2.10 g If that not work, try 2.09g. or molar mass ma88 does 2'll gi

Comment if any problem.