Question

Question 11 Not yet answered Marked out of 1.00 p Flag question Two isotropic sources, both fed with the same amplitude and a 0 degrees phase difference, what is the minimum spacing between the elements required in order to form at least one null in the array factor: Select one: a. ob.312 O C.NA d. N2 Next page

Answer 1

7. For N = 10 and d = λ/4, the major lobe of the ordinary end-fire is wider (HPBW = 74◦ ) than that of the Hansen-Woodyard (HPBW = 37◦ ); thus, higher directivity for the Hansen-Woodyard end-fire array.

8. Array 2 will have lowest side level because of non-uniform amplitude distribution.

sol: Array factor a sin ny sin 4/2 for 2 elements = siny = 2 cos(4/2) sinta Where Y= 2 Pd cos o = BdGS (2=0° phese shift] .: 2 Co Array Factor = 2 cop ( Bd colo) For nuus in array factor Bdoso = 1/2 or amin. = I or amin. RG20 max. for amin = min spacing aso should be max. Blw elements dmin. = I = 1/₂ (207). is,2 vector = Sol. ② - polevization loss Factor = ( St. Bk 1.o where it = transmitted unit vector at ja all A R = Received unit rector = ant j y r Right circlere putting these values into 0 . Ja l polerized] . PLE = 14 Ja