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engineering Civil-Engineering

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Answer 1

Answer #1

This can be solved by applying the principle of impulse and momentum for a rigid body

mb,mass of bullet=0.045kg

Vb,velocity of bullet=460m/s

mp,mass of panel=9kg

Vp,velocity of panel=rw=(b/2)w

where w is the angular velocity.

Vp=(200/2)x10-3w=.1w

equating impulse along with horizontal direction,

mbVbcos5+Axt=mpVp

if the horizontal component of impulsive reation at A is to be zero (A is the point about which panel rotates),

mbVbcos5+0=mpVp

0.045x460cos5+0=9.1w

20.62=.9w

w=22.91rad/s

Vp,velocity of panel=.1w=2.291m/s

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Answer 2

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