Question

OXO le Help!! Name m wheel built in 1893 had a capacity of 2,160 passengers, the current tallest “Ferris" wheel in Las Vegas has a capacity 1,120 passengers. Suppose the High Roller "Ferris" wheel with a radius of 79.25 m in Las Vegas completes a full revolution (2 radians) every 2.5 minutes when operating at its maximum speed. If this wheel were uniformly slowed from its maximum speed to a stop in 27 seconds, what would be the magnitude of the tangential acceleration at the outer rim of the wheel during its deceleration?

Answer 1

Radius of the Ferris Wheel, R = 79.25 m

Initial angular speed of the Ferris Wheel, wo = 20 radians every 2.5 minutes

= 20 / 2.5 rad/min

= 20 / (2.5 x 60) rad/s

= 0.133 rad/s

The Ferris Wheel comes to stop in 27 seconds

Suppose, angular deceleration of the wheel = $\alpha$

Write the expression of angular speed and angular deceleration,

w = wo - $\alpha$ *t

=> 0 = 0.133 - $\alpha$ *27

=> $\alpha$ = 0.133 / 27 = 0.0049 rad/s^2

Therefore, tangential deceleration of the Ferris Wheel,

a = $\alpha$ * R = 0.0049 * 79.25 m/s^2 = 0.39 m/s^2 (Answer)