Answer to the question is as follows. Please write back in case of doubts:
a. Mean age of 1st child was born for males - 25.54
b. Standard deviation for males - sqrt(Variance) = sqrt(43.605) = 6.6034
c. Mean age of 1st child was born for females - 22.79
d.Standard deviation for females = sqrt(Variance) = sqrt(28.147) = 5.305
e. The average age of 1st child born to males is generally higher by almost 2.75 years compared to females.
Since the mean and median are almost same for the groups, the central tendancy for both groups can be safely assumed to be the Mean. Also kurtosis within a range of -1,1 means a normal no skewness distribution
Even the variability of the age is more females compared to that of male. It is 6.6034 for males vs. 5.305 for females
4. Use the following charts to compare the central tendency and variability between men and women...
What does the five number tell us about the time spent on email (Hint, interpret the five number summary in plain English) and what does the Boxplot and the normality test show? Explain. Use the 1.5xIQR rule to identify possible outliers. List the cutoff points for outliers, Show your workings. Explain what you found out. (Hint: Are there any excessive time spent on email for Male(1) or Female(2) or both). GET DATA /TYPE-XLS /FILE='C: \Users\rmanda 1 \ Desktop\homework! . xls'...