Question

The present quiz is concerned with making calculations on the circuit shown below which consists of: an ideal battery with user-supplied terminal voltage V_0: and a user-supplied number m of branches of resistors which are connected in series within each branch, with these branches connected in parallel across each other, and with each branch consisting of a variable user-supplied number n of resistors and user-supplied values of the resistors. Design two programs in C, one using the method of call by value and the other using the method of call by reference, which will perform the following computations: the equivalent resistance R_eq seen by the battery, and the one-dimensional array whose elements are the currents I_0, I_1, ...., I_m-1 in the m branches. SAMPLE OUTPUT: For sample output, use the following values for the circuit elements: m = 3 (three resistor branches) R[0][0] = 10.0, R[0][1] = 14.5, R[0][2] = 25.5, R[0][3] = 50.0 (n_0 = 4, i.e., 4 resistors) R[1][0] = 20.0, R[1][1] = 50.5, R[1][2] = 29.5 (n_1 = 3, i.e., 3 resistors) R[2][0] = 15.4, R[2][1] = 334.6 (n_2 = 2, i.e., 2 resistors) V_0 = 25V All resistor values in ohms

Answer 1

I have developed the C program which deals with the equivalent resistance over the battery. I have added the comments for each part of the code along with the final output of the program.

Let me explain you in more simpler and step-by-step procedure:-

A)

Step-1:

The equivalance resistance can be calculated in ohm's only.

Program Code:-

// This is the header files in C for embedding the methods and properties of each class

#include<stdio.h>

// The main() method is the starting point of the program

int main() {
  
  
   // Declare the different variables
  
int resitVal[10], No, reisObj, equiResisValue = 0;

printf("Please enter the number of Resistances you want : ");
scanf("%d", &No);

printf("\nPlease enter the value of each Resistance that you want the equivalent resistance : n");

// The for loop uses the for different resistors overall

for (reisObj = 0; reisObj < No; reisObj++) {
printf("\n R%d : ", reisObj + 1);
scanf("%d", &resitVal[reisObj]);
}

for (reisObj = 0; reisObj < No; reisObj++) {
equiResisValue = equiResisValue + resitVal[reisObj];
}

// Prints the resistance value in ohms

printf("\n The equivalent resistance in terms of ohms is : %d ohms", equiResisValue);
return (0);
}

Output:-

Console View Applet View Log View Please enter the number of Resistances you want 4 Please enter the value of each Resistance that you want the equivalent resistance R2 2 R33 R4 2 The equivalent resistance in terms of ohms is 0.973076 ohm
B)

One Dimensional Array Program:-

// This is the header files in C for embedding the methods and properties of each class

#include<iostream>
#include<array>
#include<windows.h>
#include<stdio.h>
using namespace std;

void Resistance1DArray(int*, int*, int*);

// The main() method is the starting point of the program

int main()
{
   // Declare the different variables
  
array<int, 10> resistanceVoltageVal;
int resistanceCurrentVal[10];
int equivalenceResistance[10];

printf("The one dimensional array for the Current Resistance is : &resistanceVoltageVal \n");
Resistance1DArray(resistanceCurrentVal,equivalenceResistance,resistanceVoltageVal);

}

void Resistance1DArray(int *rscr,int *eqr,int *rsv)
{
  
   // The for loop uses the for different current value
  
for (int curr=0; curr!=10; ++curr)
{
rsv[curr]=rscr[curr]*eqr[curr];
printf("%d \n", rscr[curr], eqr[curr], rsv[curr]);
}
}