Question

A pool is 9 feet wide by 15 feet long and is uniformly 6 feet deep....

A pool is 9 feet wide by 15 feet long and is uniformly 6 feet deep. suppose there are 3 feet of water in the pool. (density of water is 65 lb/ft^3).

what would be the work required to move a 20 lb rock from the bottom of the pool to the top.

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Answer #1

Answer. viva Ma 20 m=2016 = 2000.4536 = 9.072 Kg height h = 6ft = 6X0.3048 = 118288 m - W = mgh = 9:072 x 9.81 X/68288 = 162.

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