motion after jumping into the sled
u mg d = 0.5 m v^2
0.5* 9.8* 0.25 = 0.5* v^2
v = 1.565 m/s
using conservation of momentum
m1 v1 = (m1 + m2) v
110* v1 = ( 110 + 250) * 1.565
v1 = 5.1 m/s
Q 7.31: A football player with a mass of 110 kg runs into a stationary tackling...
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