Question

In​ 2012, the mean rate of breaking and entering offenses​ (per 100,000​ people) in the metropolitan areas of a country was

33373337.

The standard deviation was

726726.

Assume the distribution of breaking and entering rates is approximately​bell-shaped. Complete parts a through c below.

a. What percentage of metropolitan areas would you expect to have breaking and entering rates between

26112611

and

40634063​?

nothing​%

​(Type a whole​ number.) b. What percentage of metropolitan areas would you expect to have breaking and entering rates between

18851885

and

47894789​?

nothing​%

​(Type a whole​ number.) c. If someone guessed that the breaking and entering rate in one metropolitan area was

90499049​,

would this number be consistent with the data​ set?

First find the upper bound for three standard deviations from the mean.

The upper bound that represents three standard deviations from the mean is

nothing.

​(Type a whole​ number.)

Is

90499049

consistent with the data​ set?

A.​No, because

90499049

falls exactly three standard deviations away from the​ mean, and it is therefore unlikely that a metropolitan area would have this value.

B.​Yes, because

90499049

falls within two standard deviations of the​ mean, so it is likely a metropolitan area would have this value.

C.​No, because

90499049

falls well above three standard deviations away from the​ mean, and it is therefore unlikely that a metropolitan area would have this value.

D.​Yes, because

90499049

falls within one standard deviation of the​ mean, so it is likely a metropolitan area would have this value.

Answer 1

Ans: Goven data, Mean (M)= 3337, std dev (o)= 726 « P (2011<x< 1063) X-си pl 4063-3337 2611-3337 726 c 726 (68 do P(+2221 According to empirical role 68% of data les wathon one standard deration from means 18152 x 14 1885- 3337 х- 4789 - 3337 726 726 195 do = P(-22 Z22) Accordong to emperocal rule, 95to of data les within two standald deviations from mean. 9049-3337 7.87 No, because 9049 falls well above 3 sted derations away from mean, so it is unlikely that a metropolitan would have this value option ③ Correct. 2 = 726