Question

Suppose that an HPLC column produces Gaussian peaks. The detector measures absorbance at 254 nm. A sample containing equal moles of A and B was injected into the column. Compound A (€254 = 3.21 x 104 M-1 cm1) has a height of 150. mm and a half width W1/2 = 12.5 mm. Compound B (€254 = 1.51 x 104 m 1 cm-1) has w1/2 = 8.5 mm. The height of peak B is mm.

Answer 1

here AUC is area under the concentration cureve

hope you understood. thanks

Compound parameters € 254 12.5mm 3.21*104 1.518104 2 Peak Height 150 mm 8.5 mm so half peak width There is an equation ; AUC=1.064xbxw.os. AUG & E. ce Aula _EA Auch EB AUCB = AUCA X EB CA AUCA = 1.064 x 150 x 12.5mm - 1995 mm? AUS - AUCA * EG 1995*( 3.24x104,En ८१ 51x104 - EB. 938.45 mm² - 1995 & 1.51820s .. = 3.21x104 bB = AUCB = 938.45 1. Obu x WOSB 1.064 x 8.5 = 103.76 ~ 103.8 mm