Question

The yellow molecules (Y₃) react with the blue molecules(B₂) to form molecules of Y₂B in thecontainer shown below. Each circle represents one mole of material,and the atomic masses of Y and B are 57.7 and 89.5,respectively.
(There are 12 molecules of Y and 6 molecules of B in thecontainer)

1. How many grams of Y₃ and B₂ are in thecontainer?
2. How many moles of Y₂B molecules can be produced?
3. How many grams of Y₂B could be produced?
4. How many moles of Y₃ and B₂ remain aftercomplete reaction? Note: at least one of the substances mustdisappear completely.

Answer 1

In the container there are 12 molecules of Y and 6molecules of B are present.The totalweigt of the container is

                               = 57.7*12 + 89.5 = 692.4 + 537

hence there is a presence of 4 molecules ofy₃ and three molecules of B₂

1) The weight of Y3 present in the container is =4*173.1 = 692.4gm

                                                              B2    = 3*179    = 537gm

2) and 3) acc.to the following equation

                      4Y₃ + 3B₂          6Y₂B

                                                                   = 6* 204.9=1229 gm Y2B present in the container

4) finally there is no amount of reactants areremained.