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11.) Use the Ratio Test to determine the convergence or divergence of the series (3n)! n=0 12.) Use the Root Test to determin

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Solution: ਟੋ ਤੇ = (3)! (+1) {+1}}! £ = |z+l ਪੈਂ, = (2+1)! (3) ! (3{z +1) !3! (3) !(+1)/(+1)! »l (3(+1)}। (38) ! +1}{x+1)। {+72 1 = lim + 1 + 3n+2 3n+2) 3 lim (3n+1) 20 lim 1 → elle + lim 3n+2 170 3n+2 lim (30 +1) 3 lim 200 3n+2 1 lim 200 2 3+ 72 lim

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