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Consider the matrix A. [ 300 A = 120 L-6 7 -1 Find the characteristic polynomial for the matrix A. (Write your answer in term

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The giren matrix is, I soo A=1 i 2o1 Then L67-Il the characteristies pollynomial ab A is det (A-ai) , I is 3x3 identity matritot Ex be the eigen-space correspondings to The ergen value di Ep ={XE1RS: Ax=ax? = x612): (A-11)x=07 , 1,0 are 3*3 identityар For The ergenvalue &=2 E) = {x ttp® : (А-2:)x=o _нэ (R-2J)x=0. - Г-а о отсут 2-4 о 11 м2 = 1 - 6 1 -2-|] [ 42 ] 1 ТЪТ А тоFor The eigenvalue a=3. Egy = {x&p9: (A-31)x=0} Now, (A-31)X = 0 [ 3-3 oo Tat tot I 2-3 o 11 U2=lolo L-6 7 -1-3/U3] Lol JooolTherefore, Basis of the eigm space E, (corresponding to a=-1) eigen-space E2 For The ( corresponds to 2=2) for the eigen-spac

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