(7.) A particle with a charge of +2.0 mC and a mass of 5 x 10-6 kg passes through point A with a speed of 20 m/s and through point B with a speed of 50 m/s. Using the principle of conservation of energy, find (VA – VB), the potential difference between the points A and B.
Which point is at a higher potential? Does your answer make sense? Explain. [10 points]
A particle with a charge of -1.3 uc and a mass of 2.2 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 37 m/s. The only force acting on the particle is the electric force. (a) Which point is at the higher potential? point A point B Give your reasoning. Negative charge accelerates from a lower potential to a higher potential. Negative charge accelerates from a higher potential...
A particle with a charge of -4.5 μC and a mass of 3.1 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 33 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then...
A particle with a charge of -3.4 μC and a mass of 4.2 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 56 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then...
A particle with a charge of -4.4 μC and a mass of 3.5 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 26 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VBis less than VA, then give...
2. E A particle with a charge of -1.,5 uC and a mass of 2.5 x 10 kg is re- 13 Teased from rest at point A and accelerates toward point B, arriving there with a speed of 42 m/s. The only force acting on the particle is the electric force. 14 (a) Which point is at the higher potential? Give your reasoning. (b) What is int the potential difference VB -VA between A and B? ato
A particle with a charge of 1.8 μС ad a mass of 2.6 x 10 6 kg is released rom rest at pont A and accelerates toward point B am ving here w th a speed of 54 m s Theo t/fonce acting on the particle is What is the potential difference V VA between A and B? If Vs is greater than VA, then give the answer as a positive number. If Vb is less than VA, then give...
A particle with a charge of -1.6 JC and a mass of 2.6 x 10 kg is released from rest at point A and accelerates toward point 8, arriving there with a speed of 43 m/s. The only force acting on the particle is the electric force. (a) Which point is at the higher potential? O point A O point B Give your reasoning. Negative charge accelerates from a lower potential to a higher potential Negative charge accelerates from a...
A small particle has charge q and mass 2.00×10-4 kg. It moves from point A, where the electric potential is VA = +400 V, to point B, where the electric potential is VB = +800 V. The electric force is the only force acting on the particle. The particle has speed 5.00 m/s at point A, and a speed of 4.25 m/s at point B. What is the charge of the particle q?
A particle with a charge of -1.5 micro C and a mass of 2.5 x 10^-6 kg is released from rest at point A and accelerates towards point B, arriving there at a speed of 42 m/s (a) What is the potential difference between Point A and B? (b) Which point is at higher potential and explain why
A small particle has charge -2.10 μC and mass 2.20×10−4 kg. It moves from point A, where the electric potential is VA = 120 V, to point B, where the electric potential VB = 570 V. The electric force is the only force acting on the particle. The particle has a speed of 5.40 m/s at point A. What is the speed at point B? **Please show work and enter the answer in = m/s **