If the relative error of m is 1% and of h is .5%, what is the error of log(mh)?
log(mh) = log(m) + log(h)
diffrentiating both side
d(mh)/mh = dm/m + dh/h
d(mh)/mh = 0.01 + 0.005 = 0.015
=> error of log(mh) = 1.5%
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