pH = pKa + log [ salt / acid]
or pOH = pKb + log [ salt /base]
pKb of methylamine = 3.38
Intial pH :
pOH = 3.38 + log [ 0.437 / 0.213]
pOH = 3.69
pH = 14 - 3.69
pH = 10.31
After addition of 0.045 mol KOH
(CH3NH3Cl = ) CH3NH2.HCl + KOH ----> CH3NH2 + KCl + H2O
addition of KOH increases moles of CH3NH2 and decreases CH3NH3Cl
So after addition CH3NH2 = 0.213 + 0.045 = 0.258 mol / L = 0.258 M
CH3NH3Cl = 0.437 - 0.045 = 0.392 mol / L = 0.392 M
pOH = 3.38 + log [ 0.392 / 0.258]
pOH = 3.56
pH = 14 - 3.56 = 10.44
Change in pH = 10.44 - 10.31 = 0.13
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