Find the equation of the tangent line at the point (-3,2) to the curve defined implicitly below. y2 + 3y – 34 = -2x2 + 2x Select the correct answer below: O y = 2z+8 O y = 2x + 4 Oy-1-1 O y=+13 O y=-1-5 O y=x+5
QUESTION 3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x = 6t2 3y = t2= 1 o y = 1 / 8x + 1 / 2 Oy=}x+1 o y = 2/X 2/2 o y = 6x - 1 / 1
Find an equation for the line tangent to the curve at the point defined by the given value of t. 2= sint, y=6 sint, t= 7T 3 Oy=62-63 o V3 y=6x + Oy=63 Oy=-62 +63
Find an equation for the line that is tangent to the curve y = 3x3 - 3x at the point (-1,0). The equation is y=1 (Type an expression using x as the variable.)
Find an equation for the line tangent to the curve at the point defined by the given value of t. x = sin t, y = 2 sin t, t = wa y = 2x - 213 y = 2x y = 2x + 13 Oy=-2x+ 2/3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x=t, y= V2t, t = 18 y=- X-3 y=+x+3 O y = 1...
Find the equation of the tangent line to the graph of f(x) at the (x, y)-coordinate indicated below. f(x) = (2x2 + 3x + 3)(-x2 + 2); (1,8) Answer 2 Points Choose the correct answer from the options below. Oy = 9x + 17 Oy = 23x - 15 Oy = - 9x + 17 Oy = -16x + 24
1. Find an equation of the line that is tangent to the graph of f and parallel to the given line. Function Line f(x) = 2x2 2x − y + 2 = 0 y = 2.Find the slope of the graph of the function at the given point. Use the derivative feature of a graphing utility to confirm your results. f(x) = 2(2 − x)2, (6, 32) f '(6) =
Find the equation of the tangent line to the curve y = 2x cos z at the point (TT, - 2). The equation of this tangent line can be written in the form y = mx + b where m = and b=
5. (6) Find the equation of the line tangent to the curve y = f(x)=x* –2x+1 at the point (2, 13) and use it to estimate f (2.01).
Find the equation of tangent line to the curve y = x2 – \sqrt[3]{x} at the point (-1,0).