Question

3.[12] Lindsay Bluth got a job at a local boutique. They claim that 60% of clothes are discounted as part of a fire sale, but Lindsay thinks the actual proportion is more than claimed. She randomly selects 120 articles of clothes and finds that 80 have been discounted. (a) State the null and alternative hypotheses for the claim. (b) Determine the model. Check the necessary assumptions and condition for inference. (e) Calculate the P-value Hint: first find z-score (d) State the conclusion in context!

Answer 1

. ܬܝܠ let clothes P & P be the sample and population propastione of part of fire discounted sale respectivity let Semple dizebe dended by a 'I n = 120 80 0.667 p = 120 Ahe for our case, up- Nhull hypothesis P = 0.60 vis Pro.bo. b) Proportions Inp> 5 & n (l-p) >5 approximately normal if 120 x 0.667 ~ 80 > 5 &n(1-p) = 12 (1-0.667) = 39.9675 standardised proportions will be distributed Standard Nornel variete Sample observations are ماه also independent C Z-score = a N10,1) .Po folllo (where Po is 엉 value of P under Hull hypothesis) 0.667 -0.6 1.498 Rabl1-0-6) 120 - Z-score = 1.498 P valve = P(Z >1.49) (From Nound 0.0 68. Tables) Suice p-value [a=0.05 when not 0.0.68 > 0.05 gwen] -) we fail to reject Ho, et & is the level of significance x=51. & Level of significance & conclude that clain holds twe. We do not have enough evidence to that the ached proportion is more than clained,