heat loss by cu = heat gained by cu ( as there is no heat transfer to water)
Mc Cpc * ( 70 - 25) = Mal Cpal * (25 - 5)
120 * 0.39 * 45 = M * 0.91 * 20
solving , Mal = 115.71 grams<=======Answere
Physics Homework Help A student drops two metallic objects into a 120-g steel container holding 150...
8- Lead pellets, each of mass 1.40 g, are heated to 200°C. How many pellets must be added to 511 g of water that is initially at 20.0°C to make the equilibrium temperature 25.0°C?Neglect any energy transfer to or from the container. 9-A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 164-g cube of copper that is initially at 87°C, and the other is a chunk of...
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